integral from 0 to t of sin(u)

Lösung

\int_{0}^{t} sin (u) d u

- cos (t) + 1

Schritte zur Lösung

\int_{0}^{t} sin (u) d u

Nutze das gemeinsame Integral :

\int sin (u) d u = - cos (u)

= [- cos (u)]_{0}^{t}

Berechne die Grenzen:

- cos (t) + 1

= - cos (t) + 1

\int_{0}^{2} \frac{1}{1 + 4 x} d x

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