integral from 0 to 1 of x(x+5)

Lösung

\int_{0}^{1} x (x + 5) d x

\frac{17}{6}

Dezimale

2.83333 \dots

Schritte zur Lösung

\int_{0}^{1} x (x + 5) d x

Multipliziere aus

x (x + 5) : x^{2} + 5 x

= \int_{0}^{1} x^{2} + 5 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} 5 x d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 5 x d x = \frac{5}{2}

= \frac{1}{3} + \frac{5}{2}

Vereinfache

\frac{1}{3} + \frac{5}{2} : \frac{17}{6}

= \frac{17}{6}

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