integral from-4 to 1 of |x+2|

Lösung

\int_{- 4}^{1} ∣ x + 2 ∣ d x

\frac{13}{2}

Dezimale

6.5

Schritte zur Lösung

\int_{- 4}^{1} ∣ x + 2 ∣ d x

Entferne die Extremwerte

= \int_{- 4}^{- 2} - x - 2 d x + \int_{- 2}^{1} x + 2 d x

\int_{- 4}^{- 2} - x - 2 d x = 2

\int_{- 2}^{1} x + 2 d x = \frac{9}{2}

= 2 + \frac{9}{2}

Vereinfache

2 + \frac{9}{2} : \frac{13}{2}

= \frac{13}{2}

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