derivative of x^3+bx^2+cx+d

Lösung

\frac{d}{d x} (x^{3} + b x^{2} + c x + d)

3 x^{2} + 2 b x + c

Schritte zur Lösung

\frac{d}{d x} (x^{3} + b x^{2} + c x + d)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (b x^{2}) + \frac{d}{d x} (c x) + \frac{dd}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (b x^{2}) = 2 b x

\frac{d}{d x} (c x) = c

\frac{dd}{d x} = 0

= 3 x^{2} + 2 b x + c + 0

Vereinfache

= 3 x^{2} + 2 b x + c

\frac{\partial}{\partial y} (sin (x y) + x sin (y))

n = 0 \sum \infty (\frac{5}{5})^{n}

x y^{^{'}} + 5 y = x^{3} - x

\frac{\partial}{\partial s} (s \cdot cos (t))

f (x) = 6 cos (2 x)