integral from 1 to 2 of x/y+y/x

Lösung

\int_{1}^{2} \frac{x}{y} + \frac{y}{x} d y

x ln (2) + \frac{3}{2 x}

Schritte zur Lösung

\int_{1}^{2} \frac{x}{y} + \frac{y}{x} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{x}{y} d y + \int_{1}^{2} \frac{y}{x} d y

\int_{1}^{2} \frac{x}{y} d y = x ln (2)

\int_{1}^{2} \frac{y}{x} d y = \frac{3}{2 x}

= x ln (2) + \frac{3}{2 x}

\int_{1}^{2 x} \frac{1}{1 + t ^{3}} d t

\int_{0}^{2} 2 x 12 - x^{2} d x

\int_{0}^{a x} e^{- t^{2}} d t

\int_{0}^{2} 6 - x^{2} - x d x

\int_{- 3}^{3} 2 x^{2} d x