integral from-1 to 2 of x^3sqrt(x^4+3)

Lösung

\int_{- 1}^{2} x^{3} x^{4} + 3 d x

\frac{19 19 - 8}{6}

Dezimale

12.46984 \dots

Schritte zur Lösung

\int_{- 1}^{2} x^{3} x^{4} + 3 d x

Wende U-Substitution an

= \int_{4}^{19} \frac{u}{4} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{4}^{19} u d u

Wende die Potenzregel an

= \frac{1}{4} [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{19}

Berechne die Grenzen:

\frac{38 19}{3} - \frac{16}{3}

= \frac{1}{4} (\frac{38 19}{3} - \frac{16}{3})

Vereinfache

= \frac{19 19 - 8}{6}

\int_{- 4}^{- 3} \frac{1}{x - 3} d x

\int_{- 1}^{216} x^{- \frac{1}{3}} d x

\int_{1}^{- 1} (6 x + 5)^{2} d x

\int_{0}^{2} (3 t - 1)^{68} d t

\int_{0}^{1} x e^{- 8 x} d x