What is the integral from 0 to 2pi of (cos(θ)) ?

The integral from 0 to 2pi of (cos(θ)) is 0

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integral from 0 to 2pi of (cos(θ))

\int_{0}^{2 π} (cos (θ)) d θ

0

Solution steps

\int_{0}^{2 π} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= [sin (θ)]_{0}^{2 π}

Compute the boundaries:

0

= 0

\int_{- x}^{x} sin (t) d t

\int_{2}^{\infty} 9 x^{- 2} d x

\int_{0}^{t} \frac{1 - e ^{u}}{u} d u

\int_{0}^{2 π} cos (x) \cdot sin (x) d x

\int_{1}^{3} cos (x) + e^{x} - 2 x d x

What is the integral from 0 to 2pi of (cos(θ)) ?
The integral from 0 to 2pi of (cos(θ)) is 0