integral from 1 to 6 of |3x-9|

Lösung

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

\frac{39}{2}

Dezimale

19.5

Schritte zur Lösung

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

Entferne die Extremwerte

= \int_{1}^{3} - 3 x + 9 d x + \int_{3}^{6} 3 x - 9 d x

\int_{1}^{3} - 3 x + 9 d x = 6

\int_{3}^{6} 3 x - 9 d x = \frac{27}{2}

= 6 + \frac{27}{2}

Vereinfache

6 + \frac{27}{2} : \frac{39}{2}

= \frac{39}{2}

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