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人気のある微分積分 >

integral from 2 to x^3 of 1/(p^2)

解

\int_{2}^{x^{3}} \frac{1}{p ^{2}} d p

解

- \frac{1}{x ^{3}} + \frac{1}{2}

解答ステップ

\int_{2}^{x^{3}} \frac{1}{p ^{2}} d p

べき乗則を適用する

= [- \frac{1}{p}]_{2}^{x^{3}}

限度を計算する:

- \frac{1}{x ^{3}} + \frac{1}{2}

= - \frac{1}{x ^{3}} + \frac{1}{2}

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