integral from 0 to 4 of |x^2-4|

Lösung

\int_{0}^{4} x^{2} - 4 d x

16

Schritte zur Lösung

\int_{0}^{4} x^{2} - 4 d x

Entferne die Extremwerte

= \int_{0}^{2} - x^{2} + 4 d x + \int_{2}^{4} x^{2} - 4 d x

\int_{0}^{2} - x^{2} + 4 d x = \frac{16}{3}

\int_{2}^{4} x^{2} - 4 d x = \frac{32}{3}

= \frac{16}{3} + \frac{32}{3}

Vereinfache

\frac{16}{3} + \frac{32}{3} : 16

= 16

\int_{1}^{2} \frac{v ^{4} + 4 v ^{8}}{v ^{5}} d v

\int_{2}^{4} ln (x + 1) d x

\int_{- 1}^{0} \frac{1}{x ^{2} + 2 x + 2} d x

\int_{1}^{3} \frac{1}{4 x - x ^{2}} d x

\int_{0}^{\frac{π}{2}} ∣ sin (x) ∣ d x