integral from 1 to 3 of 2x^2+1

Lösung

\int_{1}^{3} 2 x^{2} + 1 d x

\frac{58}{3}

Dezimale

19.33333 \dots

Schritte zur Lösung

\int_{1}^{3} 2 x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x^{2} d x + \int_{1}^{3} 1 d x

\int_{1}^{3} 2 x^{2} d x = \frac{52}{3}

\int_{1}^{3} 1 d x = 2

= \frac{52}{3} + 2

Vereinfache

\frac{52}{3} + 2 : \frac{58}{3}

= \frac{58}{3}

\int_{- 3}^{3} (x^{3} + 3 x^{2} + 2 x) d x

\int_{1}^{3} 2 x^{2} + 4 d x

\int_{- 1}^{0} 2 y + 2 d y

\int_{1}^{25} \frac{3}{x} d x

\int_{0}^{1} x e^{x + 2} d x