What is the integral from 0 to 2 of (4x^3)/5 ?

The integral from 0 to 2 of (4x^3)/5 is 16/5

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integral from 0 to 2 of (4x^3)/5

\int_{0}^{2} \frac{4 x ^{3}}{5} d x

\frac{16}{5}

Decimal

3.2

Solution steps

\int_{0}^{2} \frac{4 x ^{3}}{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{4}{5} \cdot \int_{0}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{2}

= \frac{4}{5} [\frac{x ^{4}}{4}]_{0}^{2}

Compute the boundaries:

4

= \frac{4}{5} \cdot 4

Simplify

= \frac{16}{5}

\int_{1}^{2} x e^{6 x^{2}} d x

\int_{0}^{a} e^{- t^{2}} d t

\int_{0}^{0.2} e^{- x^{2}} d x

\int_{1}^{2} x + 2 d x

\int_{- 6}^{6} 1

What is the integral from 0 to 2 of (4x^3)/5 ?
The integral from 0 to 2 of (4x^3)/5 is 16/5