What is the integral from 4.9 to 7.1 of (12x^2-6x+4) ?

The integral from 4.9 to 7.1 of (12x^2-6x+4) is 890.648

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integral from 4.9 to 7.1 of (12x^2-6x+4)

\int_{4.9}^{7.1} (12 x^{2} - 6 x + 4) d x

890.648

Solution steps

\int_{4.9}^{7.1} 12 x^{2} - 6 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.9}^{7.1} 12 x^{2} d x - \int_{4.9}^{7.1} 6 x d x + \int_{4.9}^{7.1} 4 d x

\int_{4.9}^{7.1} 12 x^{2} d x = 961.048

\int_{4.9}^{7.1} 6 x d x = 79.2

\int_{4.9}^{7.1} 4 d x = 8.8

= 961.048 - 79.2 + 8.8

Simplify

= 890.648

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What is the integral from 4.9 to 7.1 of (12x^2-6x+4) ?
The integral from 4.9 to 7.1 of (12x^2-6x+4) is 890.648