integral from 0 to 1 of (4x^3+5)

Lösung

\int_{0}^{1} (4 x^{3} + 5) d x

6

Schritte zur Lösung

\int_{0}^{1} 4 x^{3} + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x^{3} d x + \int_{0}^{1} 5 d x

\int_{0}^{1} 4 x^{3} d x = 1

\int_{0}^{1} 5 d x = 5

= 1 + 5

Vereinfache

= 6

\int_{1}^{2} \frac{1}{2 - 3 x} d x

\int_{0}^{3} \frac{x}{1 + x} d x

\int_{0}^{1} ∣ x ∣ - x^{2} d x

\int_{- \infty}^{1} e^{2 x} d x

\int_{0}^{a^{\frac{1}{3}}} x^{5} x^{6} + a^{2} d x