What is the integral from 1 to 6 of |x^2-2x-15| ?

The integral from 1 to 6 of |x^2-2x-15| is 47

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integral from 1 to 6 of |x^2-2x-15|

\int_{1}^{6} x^{2} - 2 x - 15 d x

47

Solution steps

\int_{1}^{6} x^{2} - 2 x - 15 d x

Eliminate Absolutes

= \int_{1}^{5} - x^{2} + 2 x + 15 d x + \int_{5}^{6} x^{2} - 2 x - 15 d x

\int_{1}^{5} - x^{2} + 2 x + 15 d x = \frac{128}{3}

\int_{5}^{6} x^{2} - 2 x - 15 d x = \frac{13}{3}

= \frac{128}{3} + \frac{13}{3}

Simplify

\frac{128}{3} + \frac{13}{3} : 47

= 47

\int_{0}^{2} x^{2} (2 - x) d x

\int_{0}^{3} [x] d x

\int_{0}^{\frac{π}{3}} (6 sec^{2} (x)) d x

\int_{1}^{3} x^{2} - x + 1 d x

\int_{0}^{1} \frac{1}{x ^{\frac{1}{4}}} d x

What is the integral from 1 to 6 of |x^2-2x-15| ?
The integral from 1 to 6 of |x^2-2x-15| is 47