integral from 0 to y of 1/2

Lösung

\int_{0}^{y} \frac{1}{2} d x

\frac{y}{2}

Schritte zur Lösung

\int_{0}^{y} \frac{1}{2} d x

Integral einer Konstanten :

\int a d x = a x

= [\frac{1}{2} x]_{0}^{y}

Berechne die Grenzen:

\frac{1}{2} y

= \frac{1}{2} y

Vereinfache

= \frac{y}{2}

\int_{- 1}^{1} (3 x^{2} - 8 x) d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 16) d x

\int_{x}^{2} sin (t^{4}) d t

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\int_{0}^{π} tan (x) cos^{2} (x) d x