integral from 0 to x of 1/(1+x^2)

Lösung

\int_{0}^{x} \frac{1}{1 + x ^{2}} d x

arctan (x)

Schritte zur Lösung

\int_{0}^{x} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{x}

Berechne die Grenzen:

arctan (x)

= arctan (x)

\int_{- 1}^{1} y^{2} - 1 d y

\int_{- 5}^{5} \frac{1}{x ^{3}} d x

\int_{4}^{20} x + 5 d x

\int_{- 1}^{2} e^{u + 1} d u

\int_{0}^{4} (x^{2} + 4) d x