integral from-1 to 0 of e^{sqrt(x+1)}

Lösung

\int_{- 1}^{0} e^{x + 1} d x

2

Schritte zur Lösung

\int_{- 1}^{0} e^{x + 1} d x

Wende U-Substitution an

= \int_{0}^{1} e^{u} \cdot 2 u d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} e^{u} u d u

Wende die partielle Integration an

= 2 [e^{u} u - \int e^{u} d u]_{0}^{1}

\int e^{u} d u = e^{u}

= 2 [e^{u} u - e^{u}]_{0}^{1}

Berechne die Grenzen:

1

= 2 \cdot 1

Vereinfache

= 2

\int_{7}^{10} (x - 8)^{2} d x

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