What is the integral from 0 to 2 of (x/2) ?

The integral from 0 to 2 of (x/2) is 1

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integral from 0 to 2 of (x/2)

\int_{0}^{2} (\frac{x}{2}) d x

1

Solution steps

\int_{0}^{2} \frac{x}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= \frac{1}{2} [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= \frac{1}{2} \cdot 2

Simplify

= 1

\int_{0}^{1} (5 x^{e} + 7 e^{x}) d x

\int_{0}^{2} (3 x^{2} - x + 1) d x

\int_{0}^{4} (x - 3 x) d x

\int_{0}^{1} 2 d x

\int_{0}^{5} y^{2} d y

What is the integral from 0 to 2 of (x/2) ?
The integral from 0 to 2 of (x/2) is 1