What is the integral from 0 to 3 of 2t ?

The integral from 0 to 3 of 2t is 9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 3 of 2t

\int_{0}^{3} 2 t d t

9

Solution steps

\int_{0}^{3} 2 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} t d t

Apply the Power Rule

= 2 [\frac{t ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= 2 \cdot \frac{9}{2}

Simplify

= 9

\int_{0}^{3} 2 y d y

\int_{1}^{x^{3}} \frac{g ( t )}{4 + t ^{2}} d t

\int_{1}^{7} (1 - x) (x - 7) d x

\int_{0}^{2} \frac{1}{4 x + 1} d x

\int_{2}^{3} \frac{1}{( x - 1 ) ^{2}} d x