What is the integral from-2 to-1 of-x^2-2x-x-2 ?

The integral from-2 to-1 of-x^2-2x-x-2 is 1/6

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integral from-2 to-1 of-x^2-2x-x-2

\int_{- 2}^{- 1} - x^{2} - 2 x - x - 2 d x

\frac{1}{6}

Decimal

0.16666 \dots

Solution steps

\int_{- 2}^{- 1} - x^{2} - 2 x - x - 2 d x

Simplify

= \int_{- 2}^{- 1} - x^{2} - 3 x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 2}^{- 1} x^{2} d x - \int_{- 2}^{- 1} 3 x d x - \int_{- 2}^{- 1} 2 d x

\int_{- 2}^{- 1} x^{2} d x = \frac{7}{3}

\int_{- 2}^{- 1} 3 x d x = - \frac{9}{2}

\int_{- 2}^{- 1} 2 d x = 2

= - \frac{7}{3} - (- \frac{9}{2}) - 2

Simplify

- \frac{7}{3} - (- \frac{9}{2}) - 2 : \frac{1}{6}

= \frac{1}{6}

\int_{0}^{\frac{π}{6}} 1 + (tan (x))^{2} d x

\int_{1}^{2} \frac{sinh ( ln ( x ) )}{x} d x

\int_{1}^{2} 2 - y d y

\int_{0}^{2 π} 4 sin^{2} (t) d t

\int_{0}^{π} π sin (x) d x

What is the integral from-2 to-1 of-x^2-2x-x-2 ?
The integral from-2 to-1 of-x^2-2x-x-2 is 1/6