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Popular >

integral from 1 to 4 of |2x-6|

Solution

\int_{1}^{4} ∣ 2 x - 6 ∣ d x

Solution

5

Solution steps

\int_{1}^{4} ∣ 2 x - 6 ∣ d x

Eliminate Absolutes

= \int_{1}^{3} - 2 x + 6 d x + \int_{3}^{4} 2 x - 6 d x

\int_{1}^{3} - 2 x + 6 d x = 4

\int_{3}^{4} 2 x - 6 d x = 1

= 4 + 1

Simplify

= 5

Graph

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\int_{0}^{3} (x - 4)^{3} d x

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\int_{0}^{1} (1 - x^{2})^{3} d x

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\int_{0}^{π} (sin (θ))^{2} d θ

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of |2x-6| ?
The integral from 1 to 4 of |2x-6| is 5