integral from-3 to 4 of-x+1

解答

\int_{- 3}^{4} - x + 1 d x

\frac{7}{2}

十进制

3.5

求解步骤

\int_{- 3}^{4} - x + 1 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 3}^{4} x d x + \int_{- 3}^{4} 1 d x

\int_{- 3}^{4} x d x = \frac{7}{2}

\int_{- 3}^{4} 1 d x = 7

= - \frac{7}{2} + 7

化简

- \frac{7}{2} + 7 : \frac{7}{2}

= \frac{7}{2}

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