integral from 0 to 2 of 5x^4

Lösung

\int_{0}^{2} 5 x^{4} d x

32

Schritte zur Lösung

\int_{0}^{2} 5 x^{4} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{2} x^{4} d x

Wende die Potenzregel an

= 5 [\frac{x ^{5}}{5}]_{0}^{2}

Berechne die Grenzen:

\frac{32}{5}

= 5 \cdot \frac{32}{5}

Vereinfache

= 32

\int_{1}^{2} \frac{1}{x 4 + x ^{2}} d x

\int_{0}^{2} (6 x - 6) (4 x^{2} + 5) d x

\int_{- 1}^{5} 6 x^{5} d x

\int_{π}^{\frac{3 π}{2}} ∣ sin (x) ∣ d x

\int_{5}^{x} \frac{1}{t} d t