integral from 1 to 4 of (x^2+1)^2

Lösung

\int_{1}^{4} (x^{2} + 1)^{2} d x

\frac{1248}{5}

Dezimale

249.6

Schritte zur Lösung

\int_{1}^{4} (x^{2} + 1)^{2} d x

Multipliziere aus

(x^{2} + 1)^{2} : x^{4} + 2 x^{2} + 1

= \int_{1}^{4} x^{4} + 2 x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{4} d x + \int_{1}^{4} 2 x^{2} d x + \int_{1}^{4} 1 d x

\int_{1}^{4} x^{4} d x = \frac{1023}{5}

\int_{1}^{4} 2 x^{2} d x = 42

\int_{1}^{4} 1 d x = 3

= \frac{1023}{5} + 42 + 3

Vereinfache

\frac{1023}{5} + 42 + 3 : \frac{1248}{5}

= \frac{1248}{5}

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