integral from 0 to pi/(27) of cos(9x)

Lösung

\int_{0}^{\frac{π}{27}} cos (9 x) d x

\frac{1}{6 3}

Dezimale

0.09622 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{27}} cos (9 x) d x

Wende U-Substitution an

= \int_{0}^{\frac{π}{3}} cos (u) \frac{1}{9} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int_{0}^{\frac{π}{3}} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{9} [sin (u)]_{0}^{\frac{π}{3}}

Berechne die Grenzen:

\frac{3}{2}

= \frac{1}{9} \cdot \frac{3}{2}

Vereinfache

= \frac{1}{6 3}

\int_{0}^{2} 6 - 3 x d x

\int_{0}^{1} 2^{3 x} d x

\int_{4.6}^{7} 12 x^{2} - 6 x + \frac{4}{x} d x

\int_{0}^{l n (3)} \frac{x}{x ^{2} - 3 x} d x

\int_{- 1}^{1} \frac{12}{1 + x ^{2}} d x