What is the integral from-pi to x of sin(θ) ?

The integral from-pi to x of sin(θ) is -cos(x)-1

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integral from-pi to x of sin(θ)

\int_{- π}^{x} sin (θ) d θ

- cos (x) - 1

Solution steps

\int_{- π}^{x} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{- π}^{x}

Compute the boundaries:

- cos (x) - 1

= - cos (x) - 1

\int_{- 1}^{1} x^{99} d x

\int_{0}^{2} x x^{2} + 4 d x

\int_{0}^{2} \frac{x}{1 + x} d x

\int_{0}^{20} \frac{x}{9 + 2 x} d x

\int_{π}^{2 π} cos^{2} (θ) d θ

What is the integral from-pi to x of sin(θ) ?
The integral from-pi to x of sin(θ) is -cos(x)-1