integral from 0 to 5 of (2x-5)

Lösung

\int_{0}^{5} (2 x - 5) d x

0

Schritte zur Lösung

\int_{0}^{5} 2 x - 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 2 x d x - \int_{0}^{5} 5 d x

\int_{0}^{5} 2 x d x = 25

\int_{0}^{5} 5 d x = 25

= 25 - 25

Vereinfache

= 0

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