integral from 0 to ln(5) of e^{x-e^x}

Lösung

\int_{0}^{l n (5)} e^{x - e^{x}} d x

\frac{1}{e} - \frac{1}{e ^{5}}

Dezimale

0.36114 \dots

Schritte zur Lösung

\int_{0}^{l n (5)} e^{x - e^{x}} d x

Wende U-Substitution an

= \int_{1}^{5} e^{- u} d u

Wende U-Substitution an

= \int_{- 1}^{- 5} - e^{v} d v

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 5}^{- 1} - e^{v} d v

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{- 5}^{- 1} e^{v} d v)

Nutze das gemeinsame Integral :

\int e^{v} d v = e^{v}

= - (- [e^{v}]_{- 5}^{- 1})

Vereinfache

= [e^{v}]_{- 5}^{- 1}

Berechne die Grenzen:

\frac{1}{e} - \frac{1}{e ^{5}}

= \frac{1}{e} - \frac{1}{e ^{5}}

\int_{2}^{4} (x^{2} - 6 x + 9) d x

\int_{0}^{2} (x + 5) d x

\int_{0}^{2} 5^{4 x} d x

\int_{0}^{10} k x d x

\int_{1}^{e^{4}} (5 - x) e^{x} d x