integral from 1 to 3 of x/4

Lösung

\int_{1}^{3} \frac{x}{4} d x

1

Schritte zur Lösung

\int_{1}^{3} \frac{x}{4} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{1}^{3} x d x

Wende die Potenzregel an

= \frac{1}{4} [\frac{x ^{2}}{2}]_{1}^{3}

Berechne die Grenzen:

4

= \frac{1}{4} \cdot 4

Vereinfache

= 1

\int_{0}^{1} x 4 x^{2} + 2 d x

\int_{\frac{1}{2}}^{1} (x^{- 3} - 4) d x

\int_{- 4}^{4} x^{2} 64 - x^{3} d x

\int_{0}^{0.5} e^{x - 1} d x

\int_{0}^{10} e^{- x} d x