integral from 1 to 6 of 4x^3-4x^4-3

Lösung

\int_{1}^{6} 4 x^{3} - 4 x^{4} - 3 d x

- 4940

Schritte zur Lösung

\int_{1}^{6} 4 x^{3} - 4 x^{4} - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{6} 4 x^{3} d x - \int_{1}^{6} 4 x^{4} d x - \int_{1}^{6} 3 d x

\int_{1}^{6} 4 x^{3} d x = 1295

\int_{1}^{6} 4 x^{4} d x = 6220

\int_{1}^{6} 3 d x = 15

= 1295 - 6220 - 15

Vereinfache

= - 4940

\int_{0}^{1} (2 x - x^{2}) - x^{2} d x

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\int_{0}^{1} \frac{1}{t} d t

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