integral from 0 to ln(2) of e^{-2y}

Lösung

\int_{0}^{l n (2)} e^{- 2 y} d y

\frac{3}{8}

Dezimale

0.375

Schritte zur Lösung

\int_{0}^{l n (2)} e^{- 2 y} d y

Wende U-Substitution an

= \int_{0}^{- 2 l n (2)} - \frac{1}{2} e^{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 2 l n (2)}^{0} - \frac{1}{2} e^{u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \frac{1}{2} \cdot \int_{- 2 l n (2)}^{0} e^{u} d u)

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= - (- \frac{1}{2} [e^{u}]_{- 2 l n (2)}^{0})

Vereinfache

= \frac{1}{2} [e^{u}]_{- 2 l n (2)}^{0}

Berechne die Grenzen:

\frac{3}{4}

= \frac{1}{2} \cdot \frac{3}{4}

Vereinfache

= \frac{3}{8}

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