integral from 1 to 3 of 6/(x^3)

Lösung

\int_{1}^{3} \frac{6}{x ^{3}} d x

\frac{8}{3}

Dezimale

2.66666 \dots

Schritte zur Lösung

\int_{1}^{3} \frac{6}{x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{3} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= 6 [- \frac{1}{2 x ^{2}}]_{1}^{3}

Berechne die Grenzen:

\frac{4}{9}

= 6 \cdot \frac{4}{9}

Vereinfache

= \frac{8}{3}

\int_{0}^{2} \frac{x}{2 x ^{2} + 4} d x

\int_{0}^{1} \frac{1}{( x ^{2} + 2 ) ^{2}} d x

\int_{0}^{1} (1 - y^{2}) d y

\int_{0}^{4} 8 x^{2} d x

\int_{1}^{7} (t^{2} - 2 t - 24) d t