integral from 1 to 4 of 2x^2+3x-1

Lösung

\int_{1}^{4} 2 x^{2} + 3 x - 1 d x

\frac{123}{2}

Dezimale

61.5

Schritte zur Lösung

\int_{1}^{4} 2 x^{2} + 3 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 2 x^{2} d x + \int_{1}^{4} 3 x d x - \int_{1}^{4} 1 d x

\int_{1}^{4} 2 x^{2} d x = 42

\int_{1}^{4} 3 x d x = \frac{45}{2}

\int_{1}^{4} 1 d x = 3

= 42 + \frac{45}{2} - 3

Vereinfache

42 + \frac{45}{2} - 3 : \frac{123}{2}

= \frac{123}{2}

\int_{0}^{8} 2 b x^{- \frac{1}{3}} d x

\int_{0}^{1} 6 x^{5} e^{x^{6}} d x

\int_{0}^{4} 8 x^{3} d x

\int_{x}^{x^{2} + 1} 2 x y d y

\int_{1}^{2} \frac{e ^{\frac{2}{x}}}{x ^{2}} d x