integral from 1 to 3 of 1/((x+7)^2)

Lösung

\int_{1}^{3} \frac{1}{( x + 7 ) ^{2}} d x

\frac{1}{40}

Dezimale

0.025

Schritte zur Lösung

\int_{1}^{3} \frac{1}{( x + 7 ) ^{2}} d x

Wende U-Substitution an

= \int_{8}^{10} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= [- \frac{1}{u}]_{8}^{10}

Berechne die Grenzen:

\frac{1}{40}

= \frac{1}{40}

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