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人気のある微分積分 >

integral from 2 to x^3 of 1/(t^3)

解

\int_{2}^{x^{3}} \frac{1}{t ^{3}} d t

解

- \frac{1}{2 x ^{6}} + \frac{1}{8}

解答ステップ

\int_{2}^{x^{3}} \frac{1}{t ^{3}} d t

べき乗則を適用する

= [- \frac{1}{2 t ^{2}}]_{2}^{x^{3}}

限度を計算する:

- \frac{1}{2 x ^{6}} + \frac{1}{8}

= - \frac{1}{2 x ^{6}} + \frac{1}{8}

人気の例

integral from 0 to 5 of 6

\int_{0}^{5} 6

integral from 1 to 2 of (4x^3-6)

\int_{1}^{2} (4 x^{3} - 6) d x

integral from 1/3 to 3 of 5-5/(x^2)

\int_{\frac{1}{3}}^{3} 5 - \frac{5}{x ^{2}} d x

integral from 2 to 8 of (68+47)

\int_{2}^{8} (68 + 47) d x

integral from 0 to 3 of x/(sqrt(x^2+9))

\int_{0}^{3} \frac{x}{x ^{2} + 9} d x