What is the integral from 0 to r^2 of rsin(θ) ?

The integral from 0 to r^2 of rsin(θ) is r^3sin(θ)

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integral from 0 to r^2 of rsin(θ)

\int_{0}^{r^{2}} r sin (θ) d z

r^{3} sin (θ)

Solution steps

\int_{0}^{r^{2}} r sin (θ) d z

Integral of a constant:

\int a d x = a x

= [sin (θ) rz]_{0}^{r^{2}}

Compute the boundaries:

r^{3} sin (θ)

= r^{3} sin (θ)

\int_{\frac{π}{2}}^{π} (x sin (x)) d x

\int_{- 1}^{0} - x^{2} - x d x

\int_{2}^{4} x e^{- \frac{x}{2}} d x

\int_{x}^{2} \frac{6 ( y - x )}{8} d y

\int_{0}^{1} 15 x^{2} d x

What is the integral from 0 to r^2 of rsin(θ) ?
The integral from 0 to r^2 of rsin(θ) is r^3sin(θ)