integral from-2 to-1 of 1/(x^3)+(x^3)/4

Lösung

\int_{- 2}^{- 1} \frac{1}{x ^{3}} + \frac{x ^{3}}{4} d x

- \frac{21}{16}

Dezimale

- 1.3125

Schritte zur Lösung

\int_{- 2}^{- 1} \frac{1}{x ^{3}} + \frac{x ^{3}}{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} \frac{1}{x ^{3}} d x + \int_{- 2}^{- 1} \frac{x ^{3}}{4} d x

\int_{- 2}^{- 1} \frac{1}{x ^{3}} d x = - \frac{3}{8}

\int_{- 2}^{- 1} \frac{x ^{3}}{4} d x = - \frac{15}{16}

= - \frac{3}{8} - \frac{15}{16}

Vereinfache

- \frac{3}{8} - \frac{15}{16} : - \frac{21}{16}

= - \frac{21}{16}

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