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人気のある微分積分 >

integral from 0 to 0.7 of ln(x^2+1)

解

\int_{0}^{0.7} ln (x^{2} + 1) d x

解

0.10059 \dots

解答ステップ

\int_{0}^{0.7} ln (x^{2} + 1) d x

部分積分を適用する

= [x ln (x^{2} + 1) - \int \frac{2 x ^{2}}{x ^{2} + 1} d x]_{0}^{0.7}

\int \frac{2 x ^{2}}{x ^{2} + 1} d x = 2 (- arctan (x) + x)

= [x ln (x^{2} + 1) - 2 (- arctan (x) + x)]_{0}^{0.7}

限度を計算する:

0.10059 \dots

= 0.10059 \dots

グラフ

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