(dy)/(dx)=(y^2+1)/(x^2+1)

Lösung

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

y = tan (arctan (x) + c_{1})

Schritte zur Lösung

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

Solve separable ODE:

y = tan (arctan (x) + c_{1})

y = tan (arctan (x) + c_{1})

p a r i t y y = cos (tan (x))

a re a \frac{4}{x}, 16 x, \frac{1}{16} x

\int \frac{sin ( 2 x )}{1 + cos ^{2} ( x )} d x

\int \frac{x ^{2} + 1}{( x + 1 ) ^{2}} e^{x} d x

x \to 1 + lim (x^{2} - 4 x + 3)