integral from 1 to 4 of 1/(sqrt(1+x^2))

Lösung

\int_{1}^{4} \frac{1}{1 + x ^{2}} d x

ln (17 + 4) - ln (2 + 1)

Dezimale

1.21333 \dots

Schritte zur Lösung

\int_{1}^{4} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = ln x^{2} + 1 + x

= [ln x^{2} + 1 + x]_{1}^{4}

Berechne die Grenzen:

ln (17 + 4) - ln (2 + 1)

= ln (17 + 4) - ln (2 + 1)

\int_{0}^{x} t^{2} + 4 d t

\int_{x^{2}}^{x^{4}} sin (t) d t

\int_{0}^{1 - y^{2}} x y^{2} d x

\int_{1}^{4} 2 x - 3 d x

\int_{2}^{6} 4 x d x