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人気のある微分積分 >

integral from 0 to 2 of 8*2^{-x}-2

解

\int_{0}^{2} 8 \cdot 2^{- x} - 2 d x

解

\frac{6}{ln ( 2 )} - 4

+1

十進法表記

4.65617 \dots

解答ステップ

\int_{0}^{2} 8 \cdot 2^{- x} - 2 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 \cdot 2^{- x} d x - \int_{0}^{2} 2 d x

\int_{0}^{2} 8 \cdot 2^{- x} d x = \frac{6}{ln ( 2 )}

\int_{0}^{2} 2 d x = 4

= \frac{6}{ln ( 2 )} - 4

グラフ

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