integral from 0 to 4 of 8x-x^2

Lösung

\int_{0}^{4} 8 x - x^{2} d x

\frac{128}{3}

Dezimale

42.66666 \dots

Schritte zur Lösung

\int_{0}^{4} 8 x - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 x d x - \int_{0}^{4} x^{2} d x

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} x^{2} d x = \frac{64}{3}

= 64 - \frac{64}{3}

Vereinfache

64 - \frac{64}{3} : \frac{128}{3}

= \frac{128}{3}

\int_{0}^{12} \frac{1}{2} x d x

\int_{0}^{5} (8 t - 1)^{2} d t

\int_{0}^{2 π} (cos (t))^{2} d t

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