integral from 0 to 1000 of 0.03q+0.1

Lösung

\int_{0}^{1000} 0.03 q + 0.1 d q

15100

Schritte zur Lösung

\int_{0}^{1000} 0.03 q + 0.1 d q

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1000} 0.03 q d q + \int_{0}^{1000} 0.1 d q

\int_{0}^{1000} 0.03 q d q = 15000

\int_{0}^{1000} 0.1 d q = 100

= 15000 + 100

Vereinfache

= 15100

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