integral from 0 to 1 of (4x-3x^2)

Lösung

\int_{0}^{1} (4 x - 3 x^{2}) d x

1

Schritte zur Lösung

\int_{0}^{1} 4 x - 3 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 4 x d x - \int_{0}^{1} 3 x^{2} d x

\int_{0}^{1} 4 x d x = 2

\int_{0}^{1} 3 x^{2} d x = 1

= 2 - 1

Vereinfache

= 1

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