integral from 0 to pi of-2sin(x)

Lösung

\int_{0}^{π} - 2 sin (x) d x

- 4

Schritte zur Lösung

\int_{0}^{π} - 2 sin (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{π} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - 2 [- cos (x)]_{0}^{π}

Berechne die Grenzen:

2

= - 2 \cdot 2

Vereinfache

= - 4

\int_{1}^{3} \frac{15 + 2 x ^{3}}{x ^{4}} d x

\int_{0}^{2} 1 - ∣ x - 1 ∣ d x

\int_{0}^{\frac{π}{2}} cos (x) \cdot sin (x) d x

\int_{\frac{π}{6}}^{\frac{π}{3}} tan (x) sec^{2} (x) d x

\int_{0}^{2} cos (x - 2) d x