derivative of 1+7sin(x-tan(x))

解答

\frac{d}{d x} (1 + 7 sin (x) - tan (x))

7 cos (x) - sec^{2} (x)

求解步骤

\frac{d}{d x} (1 + 7 sin (x) - tan (x))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (7 sin (x)) - \frac{d}{d x} (tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (7 sin (x)) = 7 cos (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 0 + 7 cos (x) - sec^{2} (x)

化简

= 7 cos (x) - sec^{2} (x)

\frac{d}{d x} ((x^{2} - 9)^{\frac{1}{2}})

n = 1 \sum \infty (- \frac{2}{3})^{n}

\frac{d}{d x} (ln (sec (2 x)))

\frac{d}{d x} (\frac{4 x}{( 2 x + 1 ) ^{2}})

\int \frac{( x ^{2} + 1 )}{x ^{3} + 3 x} d x