integral from-2 to 2 of x+1

Lösung

\int_{- 2}^{2} x + 1 d x

4

Schritte zur Lösung

\int_{- 2}^{2} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x d x + \int_{- 2}^{2} 1 d x

\int_{- 2}^{2} x d x = 0

\int_{- 2}^{2} 1 d x = 4

= 0 + 4

Vereinfache

= 4

\int_{- 1}^{2} e^{x + 1} d x

\int_{0}^{1} \frac{x}{1 + 6 x ^{2}} d x

\int_{0}^{4} (x^{2} + x) d x

\int_{1}^{3} (\frac{3}{4} x^{2} - 2) d x

\int_{0}^{5} (2 x - 1)^{2} d x