integral from 0 to 6 of (185)/((t+1)^2)

Lösung

\int_{0}^{6} \frac{185}{( t + 1 ) ^{2}} d t

\frac{1110}{7}

Dezimale

158.57142 \dots

Schritte zur Lösung

\int_{0}^{6} \frac{185}{( t + 1 ) ^{2}} d t

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 185 \cdot \int_{0}^{6} \frac{1}{( t + 1 ) ^{2}} d t

Wende U-Substitution an

= 185 \cdot \int_{1}^{7} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= 185 [- \frac{1}{u}]_{1}^{7}

Berechne die Grenzen:

\frac{6}{7}

= 185 \cdot \frac{6}{7}

Vereinfache

= \frac{1110}{7}

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