integral from 0 to 1 of 16x

Lösung

\int_{0}^{1} 16 x d x

8

Schritte zur Lösung

\int_{0}^{1} 16 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int_{0}^{1} x d x

Wende die Potenzregel an

= 16 [\frac{x ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= 16 \cdot \frac{1}{2}

Vereinfache

= 8

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